Answer
No.
Work Step by Step
If you push the function rightward, there is no way to recreate the original function. Therefore, there doesn't exist a positive value $a$ such that $f(x)=f(x-a)$ and the function cannot be periodic.
Functions Modeling Change: A Preparation for Calculus, 5th Edition
by Connally, Eric; Hughes-Hallett, Deborah; Gleason, Andrew M.; Cheifetz, Phil C.
Published by
Wiley
ISBN 10:
1118583191
ISBN 13:
978-1-11858-319-7
Chapter 7 - Trigonometry and Periodic Functions - Review Exercises and Problems for Chapter Seven - Page 315: 3
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