Functions Modeling Change: A Preparation for Calculus, 5th Edition

Published by Wiley
ISBN 10: 1118583191
ISBN 13: 978-1-11858-319-7

Chapter 6 - Transformations of Functions and Their Graphs - Review Exercises and Problems for Chapter Six - Page 259: 6

Answer

Even.

Work Step by Step

To find $f(-x)$, replace $x$ with $-x$ to get $f(-x)=\frac{1}{(-x)^2}=-\frac{1}{(-1)^2x^2}=\frac{1}{x^2}$. Since $f(x)=\frac{1}{x^2}$, $f(x)=f(-x)$. Therefore, by the definition of an even function, this function is even.
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