Functions Modeling Change: A Preparation for Calculus, 5th Edition

Published by Wiley
ISBN 10: 1118583191
ISBN 13: 978-1-11858-319-7

Chapter 5 - Logarithmic Functions - Review Exercises and Problems for Chapter Five - Page 226: 8

Answer

21.46

Work Step by Step

Using the rules of logarithms, we find: $$\ln \left(e^{0.15t}\right)=\ln \left(25\right) \\ 0.15t=2\ln \left(5\right) \\ t=21.46$$
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