Functions Modeling Change: A Preparation for Calculus, 5th Edition

Published by Wiley
ISBN 10: 1118583191
ISBN 13: 978-1-11858-319-7

Chapter 5 - Logarithmic Functions - 5.2 Logarithms and Exponential Models - Exercises and Problems for Section 5.2 - Skill Refresher - Page 200: S8

Answer

.402

Work Step by Step

Simplifying the expression, we find: $$\ln \left(e^{7x}\right)=\ln \left(5e^{3x}\right)\\ 7x\ln \left(e\right)=\ln \left(5\right)+3x\ln \left(e\right) \\ 7x=\ln \left(5\right)+3x \\ x=\frac{\ln \left(5\right)}{4} \\ x= .402$$
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