Functions Modeling Change: A Preparation for Calculus, 5th Edition

Published by Wiley
ISBN 10: 1118583191
ISBN 13: 978-1-11858-319-7

Chapter 5 - Logarithmic Functions - 5.1 Logarithms and Their Properties - Exercises and Problems for Section 5.1 - Exercises and Problems - Page 195: 69

Answer

-.415

Work Step by Step

Using the properties of logarithms, we find: $$e^{4t+1}=\frac{15}{29} \\ \ln \left(e^{4t+1}\right)=\ln \left(\frac{15}{29}\right) \\ 4t+1=\ln \left(\frac{15}{29}\right) \\ t=\frac{\ln \left(\frac{15}{29}\right)-1}{4} \\ t= -.415$$
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