Answer
False.
Work Step by Step
$\sqrt{\log x}$ and $\log \sqrt{x}$ ($\sqrt{x}=x^\frac{1}{2}$) are two completely different expressions, so this statement is false.
Functions Modeling Change: A Preparation for Calculus, 5th Edition
by Connally, Eric; Hughes-Hallett, Deborah; Gleason, Andrew M.; Cheifetz, Phil C.
Published by
Wiley
ISBN 10:
1118583191
ISBN 13:
978-1-11858-319-7
Chapter 5 - Logarithmic Functions - 5.1 Logarithms and Their Properties - Exercises and Problems for Section 5.1 - Exercises and Problems - Page 194: 44
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