Functions Modeling Change: A Preparation for Calculus, 5th Edition

Published by Wiley
ISBN 10: 1118583191
ISBN 13: 978-1-11858-319-7

Chapter 5 - Logarithmic Functions - 5.1 Logarithms and Their Properties - Exercises and Problems for Section 5.1 - Exercises and Problems - Page 193: 31



Work Step by Step

Take the $\ln$ of both sides to get $$\ln e^{0.12x}=\ln 100$$ Since $\ln e^a=a$ for all positive $a$, this simplifies to $$0.12x=\ln 100$$ Dividing both sides by $0.12$ yields $$x=\frac{\ln 100}{0.12}\approx38.376$$
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