Answer
True
Work Step by Step
Continuous compounding always earns more than annual compounding for the same principal P, time T and interest rate r:
Annual compounding: $$A=P(1+r)^T$$
Continuous compounding: $$A=P\cdot e^{rT}.$$
As $e^{rT}>(1+r)^T$ for any $T>0$, $r>0$, continuous compounding always yields a higher final amount than annual compounding.
