Chapter 4 - Exponential Functions - 4.5 The Number e - Exercises and Problems for Section 4.5 - Exercises and Problems - Page 176: 55

$ \lim _{t \rightarrow \infty}\left(2-3 e^{-0.2 t}\right)=2 $

The function $ e^{-0.2t}$, approaches zero as $t$ takes on larger positive numbers. Therefore: $$ \lim _{t \rightarrow \infty}\left(2-3 e^{-0.2 t}\right)=2-3 \cdot 0=2 $$