Functions Modeling Change: A Preparation for Calculus, 5th Edition

Published by Wiley
ISBN 10: 1118583191
ISBN 13: 978-1-11858-319-7

Chapter 4 - Exponential Functions - 4.3 Graphs of Exponential Functions - Exercises and Problems for Section 4.3 - Exercises and Problems - Page 164: 44

Answer

a) $P=10(2.024)^t$ b) $t=6.53$ years

Work Step by Step

(a) Given that the population grows exponentially, it can be described by $P=a b^t$, where $P$ is the number of rabbits and $t$ is the number of years which have passed. The value of $a$ represents the initial number of rabbits, so $a=10$ and $P=10 b^t$. After 5 years, there are 340 rabbits so $$ \begin{aligned} 340 & =10 b^5 \\ 34 & =b^5 \\ \left(b^5\right)^{1 / 5} & =34^{1 / 5} \\ b & \approx 2.024 . \end{aligned} $$ Hence $P=10(2.024)^t$. (b) We want to find $t$ when $P=1000$. $$\begin{aligned} 10(2.024)^t&=1000\\ 2.024^t&=100\\ t\ln 2.024&=\ln 100\\ t&=\frac{\ln 100}{\ln 2.024}\\ &\approx 6.53. \end{aligned}$$ The population will reach $1000$ rabbits in around $t=6.53$ years.
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