Functions Modeling Change: A Preparation for Calculus, 5th Edition

Published by Wiley
ISBN 10: 1118583191
ISBN 13: 978-1-11858-319-7

Chapter 3 - Quadratic Functions - Strengthen Your Understanding - Page 130: 13



Work Step by Step

This function is simply a transformation of the function $y=x^2$, which has a vertex at $(0,0)$. The $(x-h)^2$ term pushes the function $h$ units right, and the $+k$ term pushes it up $k$ units, making the new vertex located at $(h,k)$, not $(-h,k)$. The statement must be false.
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