Answer
$y=-\frac{1}{16}\cdot(x-4)^2-2$
Work Step by Step
The vertex form of the parabola is $y=a(x-4)^2-2$ and if $x=0, y=-3$, so $-3=a(16)-2\implies a=-\frac{1}{16}$.
Hence $y=-\frac{1}{16}\cdot(x-4)^2-2$.
Functions Modeling Change: A Preparation for Calculus, 5th Edition
by Connally, Eric; Hughes-Hallett, Deborah; Gleason, Andrew M.; Cheifetz, Phil C.
Published by
Wiley
ISBN 10:
1118583191
ISBN 13:
978-1-11858-319-7
Chapter 3 - Quadratic Functions - Review Exercises and Problems for Chapter Three - Page 129: 13
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