Functions Modeling Change: A Preparation for Calculus, 5th Edition

Published by Wiley
ISBN 10: 1118583191
ISBN 13: 978-1-11858-319-7

Chapter 2 - Functions - Strengthen Your Understanding - Page 114: 34



Work Step by Step

Use $f(x)=x+1$ as a counterexample. $x=f(x)-1$, so $f^{-1}(x)=x-1$. Solving for $(f(x))^{-1}$, $$(f(x))^{-1}=\frac{1}{x+1}$$ It can been seen that these two functions aren't the same, so this statement must be false.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.