Functions Modeling Change: A Preparation for Calculus, 5th Edition

$y=\frac{1}{2}\sqrt[3]{5-x}$
Add $(2y)^3$ to both sides to get $$x+(2y)^3=5$$ Subtract $x$ from both sides to get $$(2y)^3=5-x$$ Take the cube root of both sides to cancel the third power leaving $$2y=\sqrt[3]{5-x}$$ Divide both sides by $2$ to leave a solution of $$y=\frac{1}{2}\sqrt[3]{5-x}$$