Answer
(a) $
h(x)=f(x)-2 .
$
(b) $
g(x)=f(x+1)
$
(c) $
i(x)=f(x+1)-2
$
Work Step by Step
(a) Notice that the value of $h(x)$ at every value of $x$ is 2 less than the value of $f(x)$ at the same $x$ value. Thus
$$
h(x)=f(x)-2 .
$$
(b) We see that $g(0)=f(1), g(1)=f(2)$, and so on. In general,
$$
g(x)=f(x+1)
$$
(c) The values of $i(x)$ are two less than the values of $g(x)$ at the same $x$ value. Thus
$$
i(x)=f(x+1)-2
$$
