Answer
$$ 3(2)^{n-1}$$
Work Step by Step
We see that each term is twice the last term. Thus, the first four terms are:
$$3,6,12,24$$
We find that the general form, therefore, will be:
$$ 3(2)^{n-1}$$
Functions Modeling Change: A Preparation for Calculus, 5th Edition
by Connally, Eric; Hughes-Hallett, Deborah; Gleason, Andrew M.; Cheifetz, Phil C.
Published by
Wiley
ISBN 10:
1118583191
ISBN 13:
978-1-11858-319-7
Chapter 13 - Sequences and Series - 13.1 Sequences - Exercises and Problems for Section 13.1 - Exercises and Problems - Page 540: 42
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