## Functions Modeling Change: A Preparation for Calculus, 5th Edition

$55$
We know that $a_n=a_1+(n-1)d.$ where $d$=common difference and $a_1$= the first term Hence, here we have $a_n=10+(n-1)\cdot5=10+5n-5=5n+5$ Therefore $a_{10}=5\cdot10+5=50+5=55.$