Answer
$55$
Work Step by Step
We know that $a_n=a_1+(n-1)d.$
where $d$=common difference and $a_1$= the first term
Hence, here we have
$a_n=10+(n-1)\cdot5=10+5n-5=5n+5$
Therefore $a_{10}=5\cdot10+5=50+5=55.$
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