Functions Modeling Change: A Preparation for Calculus, 5th Edition

Published by Wiley
ISBN 10: 1118583191
ISBN 13: 978-1-11858-319-7

Chapter 13 - Sequences and Series - 13.1 Sequences - Exercises and Problems for Section 13.1 - Exercises and Problems - Page 539: 24

Answer

$55$

Work Step by Step

We know that $a_n=a_1+(n-1)d.$ where $d$=common difference and $a_1$= the first term Hence, here we have $a_n=10+(n-1)\cdot5=10+5n-5=5n+5$ Therefore $a_{10}=5\cdot10+5=50+5=55.$
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