Functions Modeling Change: A Preparation for Calculus, 5th Edition

Published by Wiley
ISBN 10: 1118583191
ISBN 13: 978-1-11858-319-7

Chapter 11 - Polynomial and Rational Functions - Strengthen Your Understanding - Page 489: 8



Work Step by Step

Note that for decreasing values near $0$, $f(\frac{1}{10})=\frac{1}{1/10}=10$ and $f(\frac{1}{1000})=\frac{1}{1/1000}=1000$ However, for increasing values near $0$, $f(-\frac{1}{10})=\frac{1}{-1/10}=-10$ and $f(-\frac{1}{1000})=\frac{1}{-1/1000}=-1000$ Therefore, from the negative side, the function approaches $-\infty$ and from the positive side the function approaches $+\infty$. Therefore, this statement is false.
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