## Functions Modeling Change: A Preparation for Calculus, 5th Edition

$=\frac{6y^2+7}{y^3}$
Since $\frac{y^2}{y^3}=\frac{1}{y^1}$, rewrite the expression as $$\frac{6y^2}{y^3}+\frac{7}{y^3}=\frac{6y^2+7}{y^3}$$