Answer
$=\frac{6y^2+7}{y^3}$
Work Step by Step
Since $\frac{y^2}{y^3}=\frac{1}{y^1}$, rewrite the expression as $$\frac{6y^2}{y^3}+\frac{7}{y^3}=\frac{6y^2+7}{y^3}$$
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