Answer
$$x=0,\:x=-\frac{5}{2},\:x=3$$
Work Step by Step
Factoring the equation (as necessary) and setting the factors equal to zero, we find:
$$4x\left(2x^2-x-15\right) \\ 4x\left(2x+5\right)\left(x-3\right) \\ x=0,\:x=-\frac{5}{2},\:x=3$$
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