## Functions Modeling Change: A Preparation for Calculus, 5th Edition

$$x=0,\:x=-\frac{5}{2},\:x=3$$
Factoring the equation (as necessary) and setting the factors equal to zero, we find: $$4x\left(2x^2-x-15\right) \\ 4x\left(2x+5\right)\left(x-3\right) \\ x=0,\:x=-\frac{5}{2},\:x=3$$