Answer
$f(x)=\dfrac{5}{28}x^{7/5}$
Work Step by Step
Here, $f(x)=\dfrac{kx^{n+1}}{n+1} ~~~~(1)$
We are given that $f(x)=\dfrac{\sqrt[5] {x^2}}{4}$
Plug $k=\dfrac{1}{4}$and $n=\dfrac{2}{5}$ in equation (1) to obtain:
$f(x)=\dfrac{\dfrac{1}{4}x^{2/5+1}}{\dfrac{2}{5}+1}$
Thus, we can express the function as: $f(x)=\dfrac{5}{28}x^{7/5}$