Answer
$\dfrac{x^2+3x+1}{x+1}$
Work Step by Step
We perform the given operation and then combine like terms as necessary in order to simplify.
$f(\dfrac{1}{x})+\dfrac{1}{f(x)}=\dfrac{1}{\dfrac{1}{x}+1}+\dfrac{1}{1/x+1}\\=\dfrac{x+(x+1)(1+x)}{1+x}\\=\dfrac{x+x^2+2x+1}{1+x}\\=\dfrac{x^2+3x+1}{x+1}$