Functions Modeling Change: A Preparation for Calculus, 5th Edition

Published by Wiley
ISBN 10: 1118583191
ISBN 13: 978-1-11858-319-7

Chapter 1 - Linear Functions and Change - Exercises and Problems for Section 1.1 - Skill Refresher: S7

Answer

The answer is $1$.

Work Step by Step

We insert $x = -1$ in $\frac{3}{2 - x^3}$: $\frac{3}{2 - x^3} = \frac{3}{2 - (-1)^3} = \frac{3}{2 - ((-1) \cdot (-1) \cdot(-1) ) } = \frac{3}{2 - (-1)} = \frac{3}{2 +1 } = \frac{3}{3} = 1$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.