Answer
The answer is $1$.
Work Step by Step
We insert $x = -1$ in $\frac{3}{2 - x^3}$:
$\frac{3}{2 - x^3} = \frac{3}{2 - (-1)^3} = \frac{3}{2 - ((-1) \cdot (-1) \cdot(-1) ) } = \frac{3}{2 - (-1)} = \frac{3}{2 +1 } = \frac{3}{3} = 1$.
Functions Modeling Change: A Preparation for Calculus, 5th Edition
by Connally, Eric; Hughes-Hallett, Deborah; Gleason, Andrew M.; Cheifetz, Phil C.
Published by
Wiley
ISBN 10:
1118583191
ISBN 13:
978-1-11858-319-7
Chapter 1 - Linear Functions and Change - Exercises and Problems for Section 1.1 - Skill Refresher - Page 6: S7
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