## Functions Modeling Change: A Preparation for Calculus, 5th Edition

$$-7$$
Initial Equation: $$\frac{(1-3^{2})-(1-4^{2})}{3-4}$$ First, do the operations inside the parenthesis involving exponents: $$\frac{(1-9)-(1-16)}{3-4}$$ Then do the subtraction inside the parenthesis: $$\frac{-8-(-15)}{3-4}$$ Then preform the indicated operations in the numerator and denominator to simplify: $$\frac{7}{-1}$$ Do the division, and the final answer is $$-7$$