Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 9 - Section 9.7 - Temperature and Conversions Between the U.S. and Metric Systems - Exercise Set: 74

Answer

$\frac{170}{9}\approx18.9^\circ C$

Work Step by Step

The formula is: $C=(F-32)\times\frac{5}{9}$ where F is the Fahrenheit and C is Celsius. Here: $C=(66-32)\times\frac{5}{9}=\frac{34\times5}{9}=\frac{170}{9}\approx18.9^\circ C$
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