Answer
$9\frac{3}{4}\ yd^2$
Work Step by Step
The area of a triangle is 1\2 base times height.
$A=\frac{1}{2}(6\frac{1}{2}yd)(3yd)=\frac{1}{2}(\frac{13}{2}yd)(3yd)=\frac{39}{4}yd^2=9\frac{3}{4}yd^2$
Prealgebra (7th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321955048
ISBN 13:
978-0-32195-504-3
Chapter 9 - Section 9.3 - Area, Volume, and Surface Area - Exercise Set - Page 633: 3
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