## Prealgebra (7th Edition)

$\angle x\ and\ \angle z\ are\ 141^o$ $\angle y\ is\ 39^o$
When parallel lines are cut by a transversal, corresponding angles are equal. $\angle y$ is equal to the $39^o$ angle. $\angle x$ and the $39^o$ angle are supplementary. $\angle x=180^o-39^o=141^o$ $\angle z$ and $\angle y$ are supplementary. $\angle z=180^o-39^o=141^o$