## Prealgebra (7th Edition)

$\frac{2}{13}$
There are 4 of each card in the deck, one of each suit. There are 4 queens and 4 aces, so the probability of a queen or ace 8 of 52. $\frac{8}{52}=\frac{8\div4}{52\div4}=\frac{2}{13}$