Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 8 - Cumulative Review - Page 601: 45

Answer

$6772.12$

Work Step by Step

$4000(1+\frac{0.053}{4})^{40}$ $4000(1.01325)^{40}$ $6772.1175$
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