## Prealgebra (7th Edition)

Use the order of operations, PEMDAS, to solve. $4^3+[3^2-(10\div2)]-7\times3\longrightarrow$ parentheses $4^3+[3^2-5]-7\times3\longrightarrow$ bracket/exponent then subtract $4^3+[9-5]-7\times3\longrightarrow$ $4^3+4-7\times3\longrightarrow$ exponent $64+4-7\times3\longrightarrow$ multiply $64+4-21\longrightarrow$ add/subtract left to right $47$