Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 7 - Section 7.4 - Applications of Percent - Exercise Set - Page 507: 61

Answer

4$\frac{14}{25}$

Work Step by Step

0.12$\times$ 38 =$\frac{12}{100}$$\times$38 =$\frac{12\times38}{100}$ =$\frac{4\times3\times38}{4\times25}$ =$\frac{3\times38}{25}$ =$\frac{114}{25}$ = 4$\frac{14}{25}$
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