Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 6 - Section 6.5 - Congruent and Similar Triangles - Exercise Set - Page 452: 19


The missing length is 13.5 units

Work Step by Step

$\frac{18}{z}$=$\frac{40}{30}$ set cross products equal 40z=18$\times$30 40z=540 $\frac{40z}{40}$=$\frac{540}{40}$ Divide both sides by 40 z=13.5 The missing length is 13.5 units
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