Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 6 - Section 6.2 - Proportions - Exercise Set - Page 428: 67


3$\frac{7}{43}$$\approx$ 3.163

Work Step by Step

$\frac{43}{17}$=$\frac{8}{z}$ set cross product equal 43z =17$\times$8 multiply 43z = 136 divide by 43 both sides $\frac{43z}{43}$=$\frac{136}{43}$ z =$\frac{136}{43}$ z =3$\frac{7}{43}$ z$\approx$ 3.163 Check $\frac{43}{17}$=$\frac{8}{z}$ $\frac{43}{17}$=$\frac{8}{\frac{136}{43}}$ 43$\times$$\frac{136}{43}$=17$\times$8 multiply 136=136 true The solution is 3$\frac{7}{43}$ $\approx$3.163
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