## Prealgebra (7th Edition)

$\frac{4}{7}$
2$\frac{1}{2}$ to 5$\frac{1}{4}$ 2$\frac{1}{2}$ $\div$ 5$\frac{1}{4}$ =$\frac{2\times2+1}{2}$ $\div$ $\frac{5\times4+1}{4}$ =$\frac{5+1}{2}$ $\div$ $\frac{20+1}{4}$ =$\frac{6}{2}$ $\div$ $\frac{21}{4}$ =$\frac{6}{2}$ $\times$ $\frac{4}{21}$ =$\frac{6\times4}{2\times21}$ =$\frac{6\times4}{2\times21}$ =$\frac{3\times2\times4}{2\times3\times7}$ = $\frac{4}{7}$