Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 6 - Review - Page 460: 30


$213\frac{1}{3}\ miles$

Work Step by Step

Use cross multiplication to solve for x. $\frac{0.75\ in}{80\ mi}=\frac{2in}{x\ mi}$ $0.75x=2\times80$ $0.75x\div0.75=160\div0.75$ $x=213.3\overline3$
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