Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 6 - Review - Page 460: 24



Work Step by Step

Use cross multiplication to solve for x. $\frac{x}{4\frac{1}{2}}=\frac{2\frac{1}{10}}{8\frac{2}{5}}$ $8\frac{2}{5}(x)=({2\frac{1}{10}})(4\frac{1}{2})$ $\frac{42}{5}(x)=({\frac{21}{10}})(\frac{9}{2})$ $\frac{42}{5}(x)\times\frac{5}{42}=\frac{189}{20}\times\frac{5}{42}$ $x=\frac{\big/\!\!\!3\times9\times\big/\!\!\!7\times\big/\!\!\!5}{4\times\big/\!\!\!5\times\big/\!\!\!3\times2\times\big/\!\!\!7}=\frac{9}{8}=1\frac{1}{8}$
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