Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Section 4.8 - Solving Equations Containing Fractions - Exercise Set: 69

Answer

-36

Work Step by Step

$\frac{x}{3}$+2 =$\frac{x}{2}$ + 8 Multiply by LCD, 6 6$\frac{x}{3}$+2$\times$6 =6$\frac{x}{2}$ + 8$\times$6 Multiply by LCD, 6 $\frac{3\times2x}{3}$+2$\times$6 =$\frac{2\times3x}{2}$ +8$\times$6 2x+12=3x +48 2x+12-3x=3x +48-3x -x+12=48 -x+12 -12=48 -12 -x =36 x=-36 The solution is -36 Check Replace x with -36 $\frac{x}{3}$+2 =$\frac{x}{2}$ + 8 $\frac{-36}{3}$+2 =$\frac{-36}{2}$ + 8 $\frac{-12\times3}{3}$+2 =$\frac{-18\times2}{2}$ + 8 -12+2=-18+8 -10=-10
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