Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Section 4.7 - Operations on Mixed Numbers - Exercise Set - Page 302: 91

Answer

$1\frac{4}{5}$

Work Step by Step

$4\frac{7}{15} - 2\frac{2}{3} = 3\frac{22}{15} - 2\frac{10}{15} = 1\frac{12}{15} = 1\frac{4}{5}$
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