Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Section 4.6 - Complex Fractions and Review of Order of Operations - Exercise Set - Page 286: 77

Answer

$\frac{63}{2}$ or 31.5

Work Step by Step

$(9 + 3(4-2)) \div \frac{10}{21}$ $=(9 + 6) \div \frac{10}{21}$ $=15 \div \frac{10}{21}$ $=\frac{15}{1} \times \frac{21}{10}$ $=\frac{315}{10}$ $=\frac{63}{2}$ $=31.5$
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