Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Section 4.5 - Adding and Subtracting Unlike Fractions - Practice - Page 267: 2

Answer

$1\frac{y}{18}$

Work Step by Step

$\frac{5y}{6}+\frac{2y}{9}$ $=\frac{5y\times3}{6\times3}+\frac{2y\times2}{9\times2}$ $=\frac{15y}{18}+\frac{4y}{18}$ $=\frac{19y}{18}$ $=1\frac{1y}{18}$ $=1\frac{y}{18}$
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