Answer
$\frac{3y}{2}$
Work Step by Step
$\frac{9y}{8}$ + $\frac{2y}{8}$+$\frac{5y}{8}$-$\frac{4y}{8}$
=$\frac{9y+2y+5y-4y}{8}$
=$\frac{12y}{8}$
=$\frac{4\times 3y}
{4\times2}$
=$\frac{3y}{2}$
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