#### Answer

$\frac{3y}{2}$

#### Work Step by Step

$\frac{9y}{8}$ + $\frac{2y}{8}$+$\frac{5y}{8}$-$\frac{4y}{8}$
=$\frac{9y+2y+5y-4y}{8}$
=$\frac{12y}{8}$
=$\frac{4\times 3y}
{4\times2}$
=$\frac{3y}{2}$

Published by
Pearson

ISBN 10:
0321955048

ISBN 13:
978-0-32195-504-3

$\frac{3y}{2}$

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