#### Answer

No, it is not a solution.

#### Work Step by Step

$-\frac{1}{2}z=\frac{1}{10}$
$-\frac{1}{2}(\frac{2}{5})\overset?=\frac{1}{10}$
$-\frac{2}{10}\overset?=\frac{1}{10}\ X$

Published by
Pearson

ISBN 10:
0321955048

ISBN 13:
978-0-32195-504-3

No, it is not a solution.

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