Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Section 4.3 - Multiplying and Dividing Fractions - Exercise Set - Page 248: 79


No, it is not a solution.

Work Step by Step

$-\frac{1}{2}z=\frac{1}{10}$ $-\frac{1}{2}(\frac{2}{5})\overset?=\frac{1}{10}$ $-\frac{2}{10}\overset?=\frac{1}{10}\ X$
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