Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Section 4.2 - Factors and Simplest Form - Exercise Set: 50

Answer

18x

Work Step by Step

$\frac{270x^4y^3z^3}{15x^3y^3z^3}=\frac{270x^4y^3z^3\div15x^3y^3z^3}{15x^3y^3z^3\div15x^3y^3z^3}=\frac{18x}{1}=18x$
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