Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Review: 117

Answer

$-\frac{1}{12}$

Work Step by Step

$-\frac{3}{8}\times(\frac{2}{3}-\frac{4}{9})$ $=-\frac{3}{8}\times(\frac{6}{9}-\frac{4}{9})$ $=-(\frac{3}{8}\times\frac{2}{9})$ $=-(\frac{1}{4}\times\frac{1}{3})$ $=-\frac{1}{12}$
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