Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Review - Page 322: 116



Work Step by Step

$\frac{2+\frac{3}{4}}{1-\frac{1}{8}}$ $=(2+\frac{3}{4})\div(1-\frac{1}{8})$ $=(\frac{8}{4}+\frac{3}{4})\div(\frac{8}{8}-\frac{1}{8})$ $=\frac{11}{4}\div\frac{7}{8}$ $=\frac{11}{4}\times\frac{8}{7}$ $=\frac{11}{1}\times\frac{2}{7}$ $=\frac{22}{7}$ $=3\frac{1}{7}$
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