Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Review - Page 318: 15

Answer

$3\frac{3}{4}$

Work Step by Step

$\frac{15}{4}=15\div4=3R3=3\frac{3}{4}$
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