Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Cumulative Review - Page 326: 20



Work Step by Step

$8a+3(b-5)\ \longrightarrow$ substitute given values =$8\times5+3(9-5)\ \longrightarrow$ revolve expression in parentheses =$8\times5+3\times4\ \longrightarrow$ multiply =$40+12\ \longrightarrow$ add =$52$
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