Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 2 - Test - Page 159: 20

Answer

2

Work Step by Step

$\frac{(-3)(-2)+12}{-1(-4-5)}$ $\longrightarrow$resolve expression in parenthesis =$\frac{(-3)(-2)+12}{-1(-9)}$ $\longrightarrow$multiply =$\frac{6+12}{9}$ $\longrightarrow$simplify numerator =$\frac{18}{9}$ $\longrightarrow$divide =$2$
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