Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 2 - Section 2.5 - Order of Operations - Exercise Set: 40

Answer

25

Work Step by Step

$(2-7)^{2}$ $\div$ $(4-3)^{4}$ Simplify inside parentheses. = $(-5)^{2}$ $\div$ $(1)^{4}$ Write $(-5)^{2}$ as 25 and $1^{4}$ as 1 = 25$\div$ 1 Divide = 25
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