Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 10 - Section 10.4 - Introduction to Factoring Polynomials - Exercise Set - Page 722: 24

Answer

$9b^3+54b^2+9b=9b(b^2+6b+1)$

Work Step by Step

$9b^3+54b^2+9b$ GCF is $9b$ $9b^3+54b^2+9b=9b(b^2+6b+1)$
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